Question 614167
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Hi, 
use the given zero to find the remaining zeros of the function
h(x)=3x^4+8x^3+45x^2+128x-48; zero:-4i
Note: (x-4i)(x+4i) = (x^2 + 16)
{{{(3x^4+8x^3+45x^2+128x-48)/(x^2 + 16) = 3x^2 + 8x-3 }}}
3x^2 + 8x-3
factoring:
(3x-1)(x+3)= 0
  x = 1/3, -3     ||the remaining zeros