Question 614087
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The sum of the interior angles of any *[tex \LARGE n]-gon is given by *[tex \LARGE (n\ -\ 2)180^\circ].  Just calculate for *[tex \LARGE n\ =\ 5] and then subtract the sum of the 4 angles you know.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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