Question 614072
f(x)=x^3+2x^2-5x-6 
find the real zeros of "f"?
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Looks like x = -1 is a zero:
-1)....1....2....-5....-6
........1....1....-6....|..0

Quotient: x^2+x-6
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Factor and solve:
(x+3)(x-2) = 0
x = 2 or x = -3
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Final Answer: x = -1, 2, or, -3
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Cheers,
Stan H.