Question 611
If we subtract 3 from both sides of the equation we get
{{{sqrt(7x-3)=2x-3}}}
To get rid of the radical we square both sides of the equation
{{{7x-3=(2x+3)x(2x-3)=4x^2-12x+9}}}
{{{7x-3=4x^2-12x+9}}}
Combine like terms
{{{4x^2-19x+12=0}}}
This is a quadratic equation so we will have 2 answers
Use the quadratic equation to solve
{{{x = (19 +- sqrt( (-19)^2-4*4*12 ))/(2*4) }}}

{{{x = (19 +- sqrt( 361 - 192 ))/8}}}

{{{x = (19 +- 13)/8}}}

{{{x = 32/8}}}and{{{6/8}}}

{{{x = 4}}}and{{{3/4}}}