Question 56903
CAN SOMEONE PLEASE ASSIST:
THE LENGTH OF A RECTANGULAR GARDEN IS 8FT LESS THEN 3 TIMES ITS WIDTH. IF THE PERIMETER OF THE GARDEN IS 48FT, FIND THE DIMENSIONS OF THE GARDEN..
P=2(length+width) [Use the formula for the perimeter of a rectangle.]
P=48
Length = (3)(width)-8=(3w-8)
Width = width = w
.
48=2[(3w-8)+w] [Plug-in the values]
48=2(3w-8+w] [Simplify]
48=2(4w-8]
48=8w-16 [Solve for w]
48+16=8w
64=8w
8=w
So, the width is 8 ft.
.

To find the length:
length=(3w-8)=(3)(8)-8=24-8=16 feet
.
Check by plugging all of the values back into the original equation.
48=2(3(8)-8+8)
48=2(24)
48=48 [Checks out]