Question 613784
the length of a rectangle is 6 in more than twice the width and the perimeter is greater than 36 in what is the width of the rectangle.
let x=width of rectangle
2x+6=length of rectangle
perimeter=2*(length+width)
2(2x+6+x)>36
2(3x+6)>36
3x+6>18
3x>12
x>4
width of the rectangle >4