Question 613476
the sum of three consecutive multiples of 5 is 90. find the numbers. 

Let the first number be x.

The next number is x+5.

The next number is x+10.

x+(x+5)+(x+10)=90

x+x+5+x+10=90

combine terms

3x+15+90

Subtract 15 from both sides of the equation.

3x=75

Divide both sides of the equation by 3

x=25, x+5=30, x+10=35

Check  25+30+35=90