Question 56851
Call your first odd number 2n+1 , the second one 2n+3 and the last one 2n+5

Since the sum of the smallest and 4 times the largest is 61, we get that:

(2n+1) + 4(2n+5) = 61

2n + 1 + 8n + 20 = 61

10n = 40

n =4  => 2n+1 = 9

Answer: 9,11,13

Note: we could have solved it with x instead of 2n+1, but I wanted to show clear that it is an odd number.