Question 613170
{{{(x^2-20x+100)/(3x-30)}}}
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{{{(2x-20)/6}}}
:
Remember the rule when you divide fractions,"Invert the dividing fraction and multiply"
{{{(x^2-20x+100)/(3x-30)}}} * {{{6/(2x-20)}}}
:
We can do a lot of factoring here
{{{((x-10)(x-10))/(3(x-10))}}} * {{{6/(2(x-10))}}}
;
Cancel the 3 into the 6 
{{{((x-10)(x-10))/((x-10))}}} * {{{2/(2(x-10))}}}
:
Cancel the 2 into the 2
{{{((x-10)(x-10))/((x-10))}}} * {{{1/((x-10))}}}
;
We have two (x-10)'s in the numerator and the denominators, cancel those out and you have:
1 * 1 = 1