Question 613348
{{{5(x-4)+x=6(x-2)-8}}} Start with the given equation.



{{{5x-20+x=6x-12-8}}} Distribute.



{{{6x-20=6x-12-8}}} Combine like terms on the left side.



{{{6x-20=6x-20}}} Combine like terms on the right side.



{{{6x=6x-20+20}}} Add {{{20}}} to both sides.



{{{6x-6x=-20+20}}} Subtract {{{6x}}} from both sides.



{{{0x=-20+20}}} Combine like terms on the left side.



{{{0x=0}}} Combine like terms on the right side.



{{{0=0}}} Simplify.



Since this equation is <font size=4><b>always</b></font> true for any x value, this means x can equal any number. So there are an infinite number of solutions.