Question 613354
Find all values of x to the nearest degree that satisfy the equation 3cos2x + cosx + 2 = 0 if  0 < x < 360
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If it's {{{3cos^2(x)}}} and not 3cos(2x),
Sub u for cos(x)
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{{{3u^2 + u + 2 = 0}}}
cos(x) = u = complex numbers
I doubt you want the arccos of complex numbers.
Clarify the first term with parentheses.