Question 613327
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The numerator of your rational function has all real numbers as the domain, therefore the only points of discontinuity of the rational function are values of the independent variable that make the denominator equal zero.  Set the denominator equal to zero and solve the quadratic for the two values of the independent variable that make the rational function discontinuous.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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