Question 613306
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Let *[tex \LARGE O] represent the center of the circle.  Let *[tex \LARGE A] and *[tex \LARGE B] be the endpoints of the 10ft chord.  Construct a radius that is the perpendicular bisector of the chord.  Name the point of intersection of the radius and the chord *[tex \LARGE M].  Construct another radius through point *[tex \LARGE A].


Since the radius through *[tex \LARGE M] is a bisector of *[tex \LARGE \overline{AB}], *[tex \LARGE MA\ =\ MB\ =\ \frac{AB}{2}\ =\ 5].  Since *[tex \LARGE \overline{OM}\ \perp\ \overline{AB}], *[tex \LARGE \triangle{OMA}] is a right triangle.  Since *[tex \LARGE \overline{OA}], which is the hypotenuse of the right triangle, is a radius, *[tex \LARGE OA\ =\ 13].


Now that you have the hypotenuse and one leg of a right triangle use Pythagoras to calculate the measure of the other leg.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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