Question 613046
I'm assuming you want to factor this.




{{{14x^3+21x^2+16x+24}}} Start with the given expression



{{{(14x^3+21x^2)+(16x+24)}}} Group the terms in two pairs



{{{7x^2(2x+3)+8(2x+3)}}} Factor out the GCF {{{7x^2}}} out of the first group. Factor out the GCF {{{8}}} out of the second group



{{{(7x^2+8)(2x+3)}}} Since we have the common term {{{2x+3}}}, we can combine like terms



So {{{14x^3+21x^2+16x+24}}} factors to {{{(7x^2+8)(2x+3)}}}



In other words, {{{14x^3+21x^2+16x+24=(7x^2+8)(2x+3)}}}