Question 612944
To make things shorter, we can say {{{ln(x-2)}}} since ln (lowercase L then n) is the natural logarithm (ie log base 'e')


So we can say {{{ln(x-2) = 3}}}


Now solve for x


{{{ln(x-2) = 3}}}


{{{x-2 = e^3}}}


{{{x = e^3+2}}}