Question 612923
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Hi, 
hyperbola that has a center at (10,4), a focus at (15,4), and a vertex at (13,4)
Opens right and left,Distance of the vertices from center = 3  {{{(x-10)^2/3^3 - (y-4)^2/b^2 = 1}}}
 Distance of the foci from center = 5 = {{{sqrt(9+b^2)}}}, b = 4
{{{(x-10)^2/3^3 - (y-4)^2/4^2 = 1}}}