<PRE><B>Question 612825</B>
How many green elements are required to make this a legitimate probability distribution if there are a total of 50 elements in this sample?
x red blue orange brown green

P(x) 0.10 0.10 0.18 0.22
red is above 0.10 and so on. Green has no number.
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The missing probability is 1-(0.1+0.1+0.18+0.22) = 1-0.6 = 0.40
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# of green = 0.4*50 = 20
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Cheers,
Stan H.
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