Question 612601
(a) What is the probability of getting a sum of 8 on tossing 2 fair dice?
Ways to get "8": 6/2 ; 5/3 ; 4/4 ;3/5 ; 2*6 (5 ways)
# of random sums: 36
P(sum of 8) = 5/36
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(b) What are the odds AGAINST the even in (a) occuring?
P(not a sum of 8) = 31/36
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Odds against "sum of 8"
= P(not a sum of 8)/P(sum of 8) 
= (31/36) / (5/36) 
= 31:5
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Cheers,
Stan H.