<PRE><B>Question 612556</B>
Find four consecutive even integers such that twice the sum of the second and third exceeds 3 times the first by 34
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1st: 2x-4
2nd: 2x-2
3rd: 2x
45h: 2x+2
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Equation:
2[2x-2+2x] = 3(2x-4)+34
2(4x-2) = 6x-12+34
8x-4 = 6x+22
2x = 26
x = 13
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1st: 2x-4 = 22
2nd: 24
3rd: 26
4th: 28

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Cheers,
Stan H.
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