<PRE><B>Question 612468</B>
An averages of four tax evaders per 100 tax filers. If 50 tax filers are randomly selected from the state,
Binomial Problem with n = 50 and p(evade) = 0.04
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 what is the probability of the following: 
a. Exactly one tax filer will be a tax evader?
P(x = 1) = 50C1*0.04*0.96^49 = binompdf(50,0.04,1) = 0.2706
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b. At most three filers will be tax evaders?
binomcdf(50,0.04,3) = 0.8609
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c. Over nine filers will be tax evaders?
1 - binomcdf(50,0.04,9) = 0.00002472
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Cheers,
Stan H.
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