Question 612539
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Base change formula:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log_b(a)\ =\ \frac{\log_c(a)}{\log_c(b)}] 


Substituting *[tex \LARGE p] and *[tex \LARGE q]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log_p(q)\ =\ \frac{\log_q(q)}{\log_q(p)}]


but


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log_b(b)\ =\ 1]


So


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log_p(q)\ =\ \frac{1}{\log_q(p)}\ =\ \left(\log_q(p)\right)^{-1}]



John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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