Question 612529


{{{(3t-4)(t^2-5t+1)}}} Start with the given expression.



{{{3t(t^2-5t+1)-4(t^2-5t+1)}}} Expand.



{{{(3t)*(t^2)+(3t)*(-5t)+(3t)*(1)+(-4)*(t^2)+(-4)*(-5t)+(-4)*(1)}}} Distribute.



{{{3*t^3-15*t^2+3*t-4*t^2+20*t-4}}} Multiply.



{{{3*t^3-19*t^2+23*t-4}}} Now combine like terms.



 So {{{(3t-4)(t^2-5t+1)}}} expands to {{{3*t^3-19*t^2+23*t-4}}}.



In other words, {{{(3t-4)(t^2-5t+1)=3*t^3-19*t^2+23*t-4}}}.

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