Question 612481
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Hi, 
initial investment of $5,000 doubles in value every 6 years: (A/P = 2)
In General {{{A = P(1+r/n)^nt}}}
A = Accumulated Amount
P= principal(Initial Investment) = 
r= annual rate = .
n= periods per year = 1 
t= years = 
{{{A/P = 2 = (1+r)^6}}}
        e^(ln2/6)= 1+r
             .1225 = r, 12.25%  Simple Interest/yr
  A = P(1.225)^t
How much will the investment be worth in 18 years
6 yrs = $10,000
12 yrs = $20,000
18 yrs = $40,000