Question 612469
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Let *[tex \LARGE x] represent "another" number.  Then "One" number is *[tex \LARGE 2x\ -\ 10].  Then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (2x\ -\ 10)\ -\ x\ =\ 31]


Solve for *[tex \LARGE x]


But you aren't told in which order to take the difference, so it is also true that:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ -\ (2x\ -\ 10)\ =\ 31]


Solve for the other possible value of *[tex \LARGE x]


One way, "another" number is larger, the other way, "One" number is larger.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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