Question 612450
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Poisson is utterly inappropriate for this question.  You want the binomial distribution.


Also, you don't mention whether you are playing with an American or a European wheel.


I'll assume an American wheel and you can adjust the probability of individual success if you want a European wheel.  The probability of 5 or more is a very long and complex calculation requiring you to calculate the sum of the probability of exactly 5 plus exactly 6, and so on up through exactly 100 (a very tiny number indeed), but the probability of 5 or more is equal to 1 minus the probability of 4 or less, a much simpler calculation.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P_{100}\left(\geq{5},\frac{1}{38}\right)\ =\ 1\ -\ P_{100}\left(\leq{4},\frac{1}{38}\right)\ =\ 1\ -\ \sum_{i=0}^4\,{{100}\choose{i}}\left(\frac{1}{38}\right)^i\left(\frac{37}{38}\right)^{100\,-\,i}]


You can do your own arithmetic.


Hint:  *[tex \LARGE {{n}\choose{k}}] is the number of combinations of *[tex \Large n] things taken *[tex \Large k] at a time and is calculated by *[tex \Large \frac{n!}{k!(n\,-\,k)!}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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