Question 612391
Factoring the difference of 2 squares is something you will need to be able to do. Those type of problems come up a lot

In general {{{a^2 - b^2 = (a-b)(a+b)}}}

{{{36y^2 - z^2}}} is a difference of 2 squares. Where one term is 6y and the other is z


{{{36y^2 - z^2}}}
{{{(6y - z)(6y + z)}}}
there you go

Often you will be given term that are higher order, for example {{{16x^4 - 81y^4}}}
{{{(4x^2 - 9y^2)(4x^2 + 9y^2)}}}
And you can see that first term is still a difference of 2 squares so it can be factored again. So keep your eye open for that