Question 612182
<pre>
{{{D}}} = {{{A*B*C}}}

{{{D/(B*C)}}} = {{{(A*B*C)/(B*C)}}}

{{{D/(B*C)}}} = {{{(A*cross(B)*cross(C))/(cross(B)*cross(C))}}}

{{{D/(B*C)}}} = {{{A}}}

Edwin</pre>