<PRE><B>Question 56782</B>
find all zeroes of P(x) = 6x^4 - 7x^3 - 8x^2 + 5x.
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x(6x^3-7x^2-8x+5)=0
x=0 is a zero.
Graphing I find x=-1 is a zero.
Using synthetic I find the quotient is 6x^2-13x+5
x=[13+-sqrt(169-120)]/12
x=[13+-7]/12
x=5/3 or x=1/2
Cheers,
Stan H.</PRE>