Question 56777
The length of a rectangle is 8 in. more than twice its width. If the perimeter of the rectangle is 64 in., find the width of the rectangle.
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Let width be "w".  Then length is "2w+8".
Perimeter = 2(length + width)
64 = 2(2w+8+w)
32=3w+8
3w=24
x=8 inches = width
2w+8=24 inches = length
Cheers,

Stan H.