Question 611741
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The value of a 2X2 determinant *[tex \LARGE \left|\ a\ b\cr\ c\ d\right|]


Is calculated by *[tex \LARGE ad\ -\ cb]


Create your coefficient determinant by setting *[tex \LARGE a] and *[tex \LARGE b] in the pattern above to the coefficients on the variables in your first equation and then setting *[tex \LARGE c] and *[tex \LARGE d] to the coefficients on the variables in the second equation.  Once you have done that calculate *[tex \LARGE D], the value of the coefficient determinant.


The next step is to replace the first column in your coefficient determinant with the two constant values, 5 and -3 in your particular case.  Then calculate the value of the *[tex \LARGE x] determinant, *[tex \LARGE D_x].


Starting fresh with a new copy of the coefficient determinant, replace the SECOND column with the constant values.  Then calculate the value of the *[tex \LARGE y] determinant, *[tex \LARGE D_y]


Then Cramer's Rule says: *[tex \LARGE x\ =\ \frac{D_x}{D}] and *[tex \LARGE y\ =\ \frac{D_y}{D}]


Blows up if *[tex \LARGE D\ =\ 0], but that is not the case for your problem.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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