Question 611655
Approximate the value of log 27/49 base 12 by using log 3 base 12=0.4421 and log 7 base 12=0.7831
<pre>
{{{log(12,(27/49))}}} = 
{{{log(12,(3^3/7^2))}}} = 
{{{log(12,(3^3))}}} - {{{log(12,(7^2))}}} = 
{{{3*log(12,(3))}}} - {{{2*log(12,(7))}}} = 
{{{3*0.4421}}} - {{{2*0.7831}}} = 
-0.2399

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