Question 611636
{{{sqrt(2x+15)-x=6}}}
{{{sqrt(2x+15) = x + 6}}} now square both sides
{{{2x+15 = x^2 + 12x + 36}}} collect terms and solve for x
{{{0 = x^2 +10x + 21}}}
{{{0 = (x+3)(x+7)}}}
so x is either -3 or -7
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