Question 611367
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ x^2\ +\ 6x\ -\ 8]


Now, complete the square on the right and then collect terms to result in a function that has the following pattern:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ 4p(x\ -\ h)^2\ +\ k]


which is a parabola with a vertical axis of symmetry and a vertex of (h,k).  The parabola opens upward if *[tex \LARGE p\ >\ 0], downward otherwise.  *[tex \LARGE p] is the distance from the vertex to the focus of the parabola and *[tex \LARGE -p] is the distance from the vertex to the directrix.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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