Question 611372
<font face="Times New Roman" size="+2">


Three independent events since you are replacing the drawn card every time.  There is a 1/2 probability of getting what you want (odd or even) on any given draw.  So:  *[tex \LARGE \left(\frac{1}{2}\right)^3].  Don't know where you got the 3 in the numerator.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<div style="text-align:center"><a href="http://outcampaign.org/" target="_blank"><img src="http://cdn.cloudfiles.mosso.com/c116811/scarlet_A.png" border="0" alt="The Out Campaign: Scarlet Letter of Atheism" width="143" height="122" /></a></div>
</font>