Question 611133
f(x)=(-x^2-9x-20)/(x+4)
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Factor:
f(x) = [-(x^2+9x+20)] / (x+4)
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f(x) = [-(x+4)(x+5)] / (x+4)
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At this point you might cancel the (x+4) factors,
but you would lose the fact that f has a "hole"
at x = -4.
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Cheers,
Stan H.