Question 611084
15 liters of a mixture contains 20% alcohol and the rest water. If 3 liters of water be mixed in it, the percentage of alcohol in the new mixture will be
.
Let x = percentage of alcohol in new mixture
then
x(15+3) = .20(15)
x(18) = 3
x = 3/18
x = 0.167
x = 16.7%