Question 611020
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Hi, 
Four times the sum of twice the number and 7 exceeds the value of the number by 70. 
Good work on the 4(2n+7)
Question states***
 4(2n+7) = {{{n + 70}}}
Solving for n
 8n + 28 = n + 70
      7n = 42
       n = 6
CHECKING our Answer***
 4· (2·6 + 7) = 6 + 70 = 76