Question 56640
Help, please! Solve for y:
x^2-xy+y^2=6
Thanks!!
WRITE IT AS A QUADRATIC IN Y 
Y^2-YX+(X^2-6)=0.........COMPARING WITH STD.QUADRATIC...AY^2+BY+C=0
A=1....B=-X....C=(X^2-6)
{{{y = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{y = (x +- sqrt( x^2-4*1*(x^2-6)))/(2*1)}}} 
{{{y = (x +- sqrt(24-3x^2))/(2) }}}