Question 610928
The sixth term should be {{{16/243}}} because the nth term is {{{a[n]=(1/2)(2/3)^(n-1)}}}



So the 6th term is {{{a[6]=(1/2)(2/3)^(6-1)=(1/2)(2/3)^(5)=(1/2)(32/243)=16/243}}}