Question 610838
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Hi, 
1, 2, 3, 4, 5, 6, 7, 8, 9, and 10   ||Note: {{{10}}} chips in all, 2 Odds <5
Selecting one chip:
P(Odd 'or' number <5) = P(Odd)+ P(<5) - P(both) = 5/10 + 4/10 - 2/10 = {{{7/10}}}