Question 56647
Complete the ordered pairs so that each is a solution for the given equation
3x+4y=12 (0, ), (  ,3/4),(  ,0), (8/3, )
Let x=0 and solve for y for (0, )
3(0)+4y=12
4y=12
4y/4=12/4
y=3  (0,3) is a solution.
:
Let y=3/4 and solve for x for ( , 3/4)
3x+4(3/4)=12
3x+3=12
3x+3-3=12-3
3x=9
3x/3=9/3
x=3  (3,3/4) is a solution.
:
Let y=0 and solve for x for ( , 0)
3x+4(0)=12
3x=12
3x/3=12/3
x=4  (4,0) is a solution.
:
Let x=8/3 and solve for y for (8/3, )
3(8/3)+4y=12
8+4y=12
-8+8+4y=12-8
4y=4
4y/4=4/4
y=1  (8/3,1)
Happy Calculating!!!