Question 610764
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \mu_X\ =\ np]


Where *[tex \LARGE n] is the sample size and *[tex \LARGE p] is the probability of success on any individual trial.


For *[tex \LARGE p\ =\ 0.1], we note that *[tex \LARGE \mu_{bolt}\ =\ 0.1n]


Just substitute the sample size if you have it or leave the answer as is if not.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sigma_X\ =\ np(1\ -\ p)]


Where *[tex \LARGE n] is the sample size and *[tex \LARGE p] is the probability of success on any individual trial.


Plug in your numbers and do the arithmetic.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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