Question 610717
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Hi, 
Note: Use of [(nCx) * p^x * q^(n-x)] below:
P(0 heads in 5 flips)
Note: The probability of x successes in n trials is: 
{{{P = nCx*p^x*q^(n-x)}}} where p and q are the probabilities of success and failure respectively. 
In this case {{{p(heads) = .5}}} & q(tails) = 1/2 or .5
nCx = {{{n!/(x!(n-x)!)}}}  {{{n = 5}}} and {{{x = 0}}}
P = 5C0(.5)^0(.5)^5 = 1(.5)^0(.5)^5 = {{{ .0313}}}