Question 610590
C(n,r) = (n!)/(r!(n-r)!)


C(13,5) = (13!)/(5!*(13-5)!)


C(13,5) = (13!)/(5!*8!)


C(13,5) = (13*12*11*10*9*8!)/(5!*8!)


C(13,5) = (13*12*11*10*9)/(5!)


C(13,5) = (13*12*11*10*9)/(5*4*3*2*1)


C(13,5) = (154440)/(120)


C(13,5) = 1287


So there are 1287 ways if order doesn't matter.

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