<PRE><B>Question 610543</B>
 prove that 1-cos2x=2sin^2x
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1 - cos(2x) = 2sin^2(x)
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1 - (cos^2(x) - sin^2(x)) = 2sin^2(x)
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1-cos^2(x) + sin^2(x) = 2sin^2(x)
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sin^2(x) + sin^2(x) = 2sin^2(x)
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2sin^2(x) = 2sin^2(x)
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Cheers,
Stan H.
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