Question 610384
(2x-3) ( x-2 ) = x^2
2x^2 -7x +6 =x^2
x^2-7x+6 = 0
(x-1)(x-6) = 0
x= 1
x = 6
so x =6 
so 2x-3 =9
x-2 = 4
x =6