Question 610343
    An urn contains seven red balls, four black balls, and six green balls. If two balls are selected at random without replacement from the urn, what is the probability that a red ball and a black ball will be selected? (Round your answer to three decimal places.)
.
total balls: 7+4+6 = 17
number of red balls: 7
number of black balls: 4
.
7/17 * 4/16
7/17 * 1/4
7/68
0.10294
10.294%