<PRE><B>Question 610266</B>
three students select cards from a standard deck, without replacement. find the probability that:  
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a) all the cards have the same suit
# of ways to succeed: 4*4C3 = 4*4 = 16
# of random selections: 52C3
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P(3 card of same suit) = 16/52C3
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b) all the cards are of different suits 
(1/52)*(1/39)*(1/26) = 1/52728
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Cheers,
Stan H.</PRE>