<PRE><B>Question 609955</B>
two dice are rolled. find the probability of the following events.
A. both numbers are 4::::(1/6)^2 = 1/36
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B. the first dice fives 3 and the second gives 5
C. there is one 5 and one 6:: 2/36 = 1/18
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D. one number is even and one number is odd:::(1/2)^2 = 1/4
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E. the sum is equal to 7:::: 6/36 = 1/6
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F. the sum is equal to 11::: 2/36 = 1/18
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G. the sum is 7 or 11::: (6+2)/36 = 2/9
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H. the sum is more than 6 but less than 10:::: (6+5+4)/36 = 15/36 = 5/12
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Cheers,
Stan H.
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