Question 609927
This problem involves binomial probabilities
The binomial probability distribution is written as
P(x) = C(n,x)*p^x*(1-p)^(n-x) where n = the number of trials, x = the number of successes, and p is the probability of success
More than 5 throws means we need to compute the probability of 6 or more
P(6 or more) = 1 - P(5 or less)
P(5 or less) = P(5) + P(4) + ... P(0)
P(5) = C(13,5)*0.7^5*0.3^8 = 0.0142
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Adding up all the probabilities and subtracting from 1, we get:
P(6 or more) = 1 - 0.018 = 0.982